これが純粋なBashソリューションです。
として保存しstrip-escape-codes.sh、実行可能にしてから実行します<command-producing-colorful-output> | ./strip-escape-codes.shます。
これはすべての ANSIエスケープコード/シーケンスを取り除きます。色のみを取り除きたい場合は[a-zA-Z]、"m"。
バッシュ> = 4.0：
#!/usr/bin/env bash
# Strip ANSI escape codes/sequences [$1: input string, $2: target variable]
function strip_escape_codes() {
local _input="$1" _i _char _escape=0
local -n _output="$2"; _output=""
for (( _i=0; _i < ${#_input}; _i++ )); do
_char="${_input:_i:1}"
if (( ${_escape} == 1 )); then
if [[ "${_char}" == [a-zA-Z] ]]; then
_escape=0
fi
continue
fi
if [[ "${_char}" == $'\e' ]]; then
_escape=1
continue
fi
_output+="${_char}"
done
}
while read -r line; do
strip_escape_codes "${line}" line_stripped
echo "${line_stripped}"
done
バッシュ<4.0：
#!/usr/bin/env bash
# Strip ANSI escape codes/sequences [$1: input string, $2: target variable]
function strip_escape_codes() {
local input="${1//\"/\\\"}" output="" i char escape=0
for (( i=0; i < ${#input}; ++i )); do # process all characters of input string
char="${input:i:1}" # get current character from input string
if (( ${escape} == 1 )); then # if we're currently within an escape sequence, check if
if [[ "${char}" == [a-zA-Z] ]]; then # end is reached, i.e. if current character is a letter
escape=0 # end reached, we're no longer within an escape sequence
fi
continue # skip current character, i.e. do not add to ouput
fi
if [[ "${char}" == $'\e' ]]; then # if current character is '\e', we've reached the start
escape=1 # of an escape sequence -> set flag
continue # skip current character, i.e. do not add to ouput
fi
output+="${char}" # add current character to output
done
eval "$2=\"${output}\"" # assign output to target variable
}
while read -r line; do
strip_escape_codes "${line}" line_stripped
echo "${line_stripped}"
done
strip-ansi：github.com/chalk/strip-ansiを。