ファイルの5番目の列の値に基づいて.CSVファイルをフィルター処理し、それらのレコードを新しいファイルに出力します

次の形式の.CSVファイルがあります。

"column 1","column 2","column 3","column 4","column 5","column 6","column 7","column 8","column 9","column 10
"12310","42324564756","a simple string with a , comma","string with or, without commas","string 1","USD","12","70%","08/01/2013",""
"23455","12312255564","string, with, multiple, commas","string with or, without commas","string 2","USD","433","70%","07/15/2013",""
"23525","74535243123","string , with commas, and - hypens and: semicolans","string with or, without commas","string 1","CAND","744","70%","05/06/2013",""
"46476","15467534544","lengthy string, with commas, multiple: colans","string with or, without commas","string 2","CAND","388","70%","09/21/2013",""

ファイルの5列目には異なる文字列があります。5列目の値に基づいてファイルを除外する必要があります。たとえば、5番目のフィールドに値「string 1」のみを持つレコードを持つ現在のファイルから新しいファイルが必要だとしましょう。

このために、私は以下のコマンドを試しました、

awk -F"," ' { if toupper($5) == "STRING 1") PRINT }' file1.csv > file2.csv

しかし、それは私に次のようなエラーを投げていました：

awk: { if toupper($5) == "STRING 1") PRINT }
awk: ^ syntax error
awk: { if toupper($5) == "STRING 1") PRINT }
awk: ^ syntax error

次に、以下を使用しましたが、奇妙な出力が得られます。

awk -F"," '$5="string 1" {print}' file1.csv > file2.csv

出力：

"column 1" "column 2" "column 3" "column 4" string 1 "column 6" "column 7" "column 8" "column 9" "column 10
"12310" "42324564756" "a simple string with a comma" string 1 without commas" "string 1" "USD" "12" "70%" "08/01/2013" ""
"23455" "12312255564" "string with string 1 commas" "string with or without commas" "string 2" "USD" "433" "70%" "07/15/2013" ""
"23525" "74535243123" "string with commas string 1 "string with or without commas" "string 1" "CAND" "744" "70%" "05/06/2013" ""
"46476" "15467534544" "lengthy string with commas string 1 "string with or without commas" "string 2" "CAND" "388" "70%" "09/21/2013" ""

PS：文字列が小文字であるか大文字であるかわからないため、安全のためにtoupperコマンドを使用しました。コードの何が問題なのか、AWKを使用してパターンを検索するときに文字列のスペースが重要かどうかを知る必要があります。

awk -F '","'  'BEGIN {OFS=","} { if (toupper($5) == "STRING 1")  print }' file1.csv > file2.csv 

出力

"12310","42324564756","a simple string with a , comma","string with or, without commas","string 1","USD","12","70%","08/01/2013",""
"23525","74535243123","string , with commas, and - hypens and: semicolans","string with or, without commas","string 1","CAND","744","70%","05/06/2013",""

これがあなたの欲しいものだと思います。

CSVの問題は、標準がないことです。CSV形式のデータを頻繁に処理する必要がある場合は","、フィールドセパレーターとして使用するだけでなく、より堅牢な方法を検討することをお勧めします。この場合、PerlのText::CSVCPANモジュールはこのジョブに非常に適しています。

$ perl -mText::CSV_XS -WlanE '
    BEGIN {our $csv = Text::CSV_XS->new;} 
    $csv->parse($_); 
    my @fields = $csv->fields(); 
    print if $fields[4] =~ /string 1/i;
' file1.csv
"12310","42324564756","a simple string with a , comma","string with or, without commas","string 1","USD","12","70%","08/01/2013",""
"23525","74535243123","string , with commas, and - hypens and: semicolans","string with or, without commas","string 1","CAND","744","70%","05/06/2013",""

awk 'BEGIN {FS = "," }'  '{ (if toupper($5)  == "STRING 1") print; }'  file1.csv > file2.csv