これが高度なインデックス作成を考慮してどれほど効率的であるかは正確にはわかりませんが、これはそのための1つの方法です。
import numpy as np
a = np.array([8, 18, 5, 15, 12])
b = a[:, None] - a
# Fill lower triangle with largest negative
b[np.tril_indices(len(a))] = np.iinfo(b.dtype).min # np.finfo for float
# Put diagonals as rows
s = b.strides[1]
diags = np.ndarray((len(a) - 1, len(a) - 1), b.dtype, b, offset=s, strides=(s, (len(a) + 1) * s))
# Get maximum from each row and add initial zero
c = np.r_[0, diags.max(1)]
print(c)
# [ 0 13 3 6 -4]
編集:
あなたが探していたものではないかもしれない別の代替手段は、たとえば次のように、Numbaを使用することです:
import numpy as np
import numba as nb
def max_window_diffs_jdehesa(a):
a = np.asarray(a)
dtinf = np.iinfo(b.dtype) if np.issubdtype(b.dtype, np.integer) else np.finfo(b.dtype)
out = np.full_like(a, dtinf.min)
_pwise_diffs(a, out)
return out
@nb.njit(parallel=True)
def _pwise_diffs(a, out):
out[0] = 0
for w in nb.prange(1, len(a)):
for i in range(len(a) - w):
out[w] = max(a[i] - a[i + w], out[w])
a = np.array([8, 18, 5, 15, 12])
print(max_window_diffs(a))
# [ 0 13 3 6 -4]
これらの方法を元の方法と比較すると:
import numpy as np
import numba as nb
def max_window_diffs_orig(a):
a = np.asarray(a)
b = a - a[:, None]
out = np.zeros(len(a), b.dtype)
out[-1] = b[-1, 0]
for i in range(1, len(a) - 1):
out[i] = np.diag(b, -i).max()
return out
def max_window_diffs_jdehesa_np(a):
a = np.asarray(a)
b = a[:, None] - a
dtinf = np.iinfo(b.dtype) if np.issubdtype(b.dtype, np.integer) else np.finfo(b.dtype)
b[np.tril_indices(len(a))] = dtinf.min
s = b.strides[1]
diags = np.ndarray((len(a) - 1, len(a) - 1), b.dtype, b, offset=s, strides=(s, (len(a) + 1) * s))
return np.concatenate([[0], diags.max(1)])
def max_window_diffs_jdehesa_nb(a):
a = np.asarray(a)
dtinf = np.iinfo(b.dtype) if np.issubdtype(b.dtype, np.integer) else np.finfo(b.dtype)
out = np.full_like(a, dtinf.min)
_pwise_diffs(a, out)
return out
@nb.njit(parallel=True)
def _pwise_diffs(a, out):
out[0] = 0
for w in nb.prange(1, len(a)):
for i in range(len(a) - w):
out[w] = max(a[i] - a[i + w], out[w])
np.random.seed(0)
a = np.random.randint(0, 100, size=100)
r = max_window_diffs_orig(a)
print((max_window_diffs_jdehesa_np(a) == r).all())
# True
print((max_window_diffs_jdehesa_nb(a) == r).all())
# True
%timeit max_window_diffs_orig(a)
# 348 µs ± 986 ns per loop (mean ± std. dev. of 7 runs, 1000 loops each)
%timeit max_window_diffs_jdehesa_np(a)
# 91.7 µs ± 1.3 µs per loop (mean ± std. dev. of 7 runs, 10000 loops each)
%timeit max_window_diffs_jdehesa_nb(a)
# 19.7 µs ± 88.1 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
np.random.seed(0)
a = np.random.randint(0, 100, size=10000)
%timeit max_window_diffs_orig(a)
# 651 ms ± 26 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
%timeit max_window_diffs_jdehesa_np(a)
# 1.61 s ± 6.19 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
%timeit max_window_diffs_jdehesa_nb(a)
# 22 ms ± 967 µs per loop (mean ± std. dev. of 7 runs, 10 loops each)
最初のものは、小さい配列には少し良いかもしれませんが、大きい配列にはうまく機能しません。一方、Numbaはすべてのケースでかなり良いです。
a
か?