avg(price)を返すクエリがあります
select avg(price)
from(
select *, cume_dist() OVER (ORDER BY price desc) from web_price_scan
where listing_Type='AARM'
and u_kbalikepartnumbers_id = 1000307
and (EXTRACT(Day FROM (Now()-dateEnded)))*24 < 48
and price>( select avg(price)* 0.50
from(select *, cume_dist() OVER (ORDER BY price desc)
from web_price_scan
where listing_Type='AARM'
and u_kbalikepartnumbers_id = 1000307
and (EXTRACT(Day FROM (Now()-dateEnded)))*24 < 48
)g
where cume_dist < 0.50
)
and price<( select avg(price)*2
from( select *, cume_dist() OVER (ORDER BY price desc)
from web_price_scan
where listing_Type='AARM'
and u_kbalikepartnumbers_id = 1000307
and (EXTRACT(Day FROM (Now()-dateEnded)))*24 < 48
)d
where cume_dist < 0.50)
)s
having count(*) > 5
使用できる値がない場合に0を返す方法
from web_price_scan
は個別の選択です。ここで何が問題なのかわかりませんか?
having
なしの句を使用しても問題ありませんgroup by
(デフォルトでは単一のグループになります)。where
集計結果の条項として機能します。この場合、第1レベルのサブクエリによって5行を超える行が返された場合にのみ、行が返されます。