フィードの解析
（実際には推奨しないでください。他のオプションを参照してください。）
jQuery.getFeed({
url : FEED_URL,
success : function (feed) {
console.log(feed.title);
// do more stuff here
}
});
$.get(FEED_URL, function (data) {
$(data).find("entry").each(function () { // or "item" or whatever suits your feed
var el = $(this);
console.log("------------------------");
console.log("title : " + el.find("title").text());
console.log("author : " + el.find("author").text());
console.log("description: " + el.find("description").text());
});
});
$.ajax({
url : document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=10&callback=?&q=' + encodeURIComponent(FEED_URL),
dataType : 'json',
success : function (data) {
if (data.responseData.feed && data.responseData.feed.entries) {
$.each(data.responseData.feed.entries, function (i, e) {
console.log("------------------------");
console.log("title : " + e.title);
console.log("author : " + e.author);
console.log("description: " + e.description);
});
}
}
});
しかし、それは彼らがオンラインで到達可能であることを尊敬していることを意味します。
コンテンツの構築
フィードから必要な情報を正常に抽出したら、データを表示するために挿入するを作成します（で作成した要素DocumentFragmentをdocument.createDocumentFragment()含むdocument.createElement()）。
コンテンツを注入する
ページ上で必要なコンテナー要素を選択し、それにドキュメントフラグメントを追加し、innerHTMLを使用してコンテンツを完全に置き換えます。
何かのようなもの：
$('#rss-viewer').append(aDocumentFragmentEntry);
または：
$('#rss-viewer')[0].innerHTML = aDocumentFragmentOfAllEntries.innerHTML;
テストデータ
この質問のフィードを使用すると、これを書いている時点で次のようになります。
<?xml version="1.0" encoding="utf-8"?>
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:creativeCommons="http://backend.userland.com/creativeCommonsRssModule" xmlns:re="http://purl.org/atompub/rank/1.0">
<title type="text">How to parse a RSS feed using javascript? - Stack Overflow</title>
<link rel="self" href="https://stackoverflow.com/feeds/question/10943544" type="application/atom+xml" />
<link rel="hub" href="http://pubsubhubbub.appspot.com/" />
<link rel="alternate" href="https://stackoverflow.com/q/10943544" type="text/html" />
<subtitle>most recent 30 from stackoverflow.com</subtitle>
<updated>2012-06-08T06:36:47Z</updated>
<id>https://stackoverflow.com/feeds/question/10943544</id>
<creativeCommons:license>http://www.creativecommons.org/licenses/by-sa/3.0/rdf</creativeCommons:license>
<entry>
<id>https://stackoverflow.com/q/10943544</id>
<re:rank scheme="http://stackoverflow.com">2</re:rank>
<title type="text">How to parse a RSS feed using javascript?</title>
<category scheme="https://stackoverflow.com/feeds/question/10943544/tags" term="javascript"/><category scheme="https://stackoverflow.com/feeds/question/10943544/tags" term="html5"/><category scheme="https://stackoverflow.com/feeds/question/10943544/tags" term="jquery-mobile"/>
<author>
<name>Thiru</name>
<uri>https://stackoverflow.com/users/1126255</uri>
</author>
<link rel="alternate" href="/programming/10943544/how-to-parse-a-rss-feed-using-javascript" />
<published>2012-06-08T05:34:16Z</published>
<updated>2012-06-08T06:35:22Z</updated>
<summary type="html">
<p>I need to parse the RSS-Feed(XML version2.0) using XML and I want to display the parsed detail in HTML page, I tried in many ways. But its not working. My system is running under proxy, since I am new to this field, I don't know whether it is possible or not. If any one knows please help me on this. Thanks in advance.</p>
</summary>
</entry>
<entry>
<id>https://stackoverflow.com/questions/10943544/-/10943610#10943610</id>
<re:rank scheme="http://stackoverflow.com">1</re:rank>
<title type="text">Answer by haylem for How to parse a RSS feed using javascript?</title>
<author>
<name>haylem</name>
<uri>https://stackoverflow.com/users/453590</uri>
</author>
<link rel="alternate" href="/programming/10943544/how-to-parse-a-rss-feed-using-javascript/10943610#10943610" />
<published>2012-06-08T05:43:24Z</published>
<updated>2012-06-08T06:35:22Z</updated>
<summary type="html"><h1>Parsing the Feed</h1>
<h3>With jQuery's jFeed</h3>
<p>Try this, with the <a href="http://plugins.jquery.com/project/jFeed" rel="nofollow">jFeed</a> <a href="http://www.jquery.com/" rel="nofollow">jQuery</a> plug-in</p>
<pre><code>jQuery.getFeed({
url : FEED_URL,
success : function (feed) {
console.log(feed.title);
// do more stuff here
}
});
</code></pre>
<h3>With jQuery's Built-in XML Support</h3>
<pre><code>$.get(FEED_URL, function (data) {
$(data).find("entry").each(function () { // or "item" or whatever suits your feed
var el = $(this);
console.log("------------------------");
console.log("title : " + el.find("title").text());
console.log("author : " + el.find("author").text());
console.log("description: " + el.find("description").text());
});
});
</code></pre>
<h3>With jQuery and the Google AJAX APIs</h3>
<p>Otherwise, <a href="https://developers.google.com/feed/" rel="nofollow">Google's AJAX Feed API</a> allows you to get the feed as a JSON object:</p>
<pre><code>$.ajax({
url : document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&amp;num=10&amp;callback=?&amp;q=' + encodeURIComponent(FEED_URL),
dataType : 'json',
success : function (data) {
if (data.responseData.feed &amp;&amp; data.responseData.feed.entries) {
$.each(data.responseData.feed.entries, function (i, e) {
console.log("------------------------");
console.log("title : " + e.title);
console.log("author : " + e.author);
console.log("description: " + e.description);
});
}
}
});
</code></pre>
<p>But that means you're relient on them being online and reachable.</p>
<hr>
<h1>Building Content</h1>
<p>Once you've successfully extracted the information you need from the feed, you need to create document fragments containing the elements you'll want to inject to display your data.</p>
<hr>
<h1>Injecting the content</h1>
<p>Select the container element that you want on the page and append your document fragments to it, and simply use innerHTML to replace its content entirely.</p>
</summary>
</entry></feed>
処刑
jQueryの組み込みXMLサポートの使用
呼び出し：
$.get('https://stackoverflow.com/feeds/question/10943544', function (data) {
$(data).find("entry").each(function () { // or "item" or whatever suits your feed
var el = $(this);
console.log("------------------------");
console.log("title : " + el.find("title").text());
console.log("author : " + el.find("author").text());
console.log("description: " + el.find("description").text());
});
});
プリントアウト：
------------------------
title : How to parse a RSS feed using javascript?
author :
Thiru
https://stackoverflow.com/users/1126255
description:
------------------------
title : Answer by haylem for How to parse a RSS feed using javascript?
author :
haylem
https://stackoverflow.com/users/453590
description:
jQueryとGoogle AJAX APIの使用
呼び出し：
$.ajax({
url : document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=10&callback=?&q=' + encodeURIComponent('https://stackoverflow.com/feeds/question/10943544'),
dataType : 'json',
success : function (data) {
if (data.responseData.feed && data.responseData.feed.entries) {
$.each(data.responseData.feed.entries, function (i, e) {
console.log("------------------------");
console.log("title : " + e.title);
console.log("author : " + e.author);
console.log("description: " + e.description);
});
}
}
});
プリントアウト：
------------------------
title : How to parse a RSS feed using javascript?
author : Thiru
description: undefined
------------------------
title : Answer by haylem for How to parse a RSS feed using javascript?
author : haylem
description: undefined