指定された2つのインデックスを交換します


31

正の整数の配列と2つの異なる有効なインデックスを指定すると、2つのインデックスに対応する2つの要素が入れ替わった配列を返します。

0インデックス付けまたは1インデックス付けを選択できますが、以下のテストケースは0インデックス付けされます。

array        m n output
[1,2,3,4]    0 1 [2,1,3,4]
[5,8,9]      0 2 [9,8,5]
[11,13,15,3] 1 2 [11,15,13,3]
[11,13,15,3] 2 1 [11,15,13,3]
[11,15,15,3] 2 1 [11,15,15,3]

これはです。バイト単位の最短回答が優先されます。標準の抜け穴が適用されます。



1
ええ、これは多くのゴルフ言語が苦労するタスクですが、ほとんどの実用的な言語は簡単です。(可変要素を持つリストは、ゴルフ言語が持つ一般的なものではありません。)その場合、それは非常に興味深いでしょう。(しかし、ゴルフ言語はおそらくまだ勝ちます。なぜなら、彼らはより複雑なので、より複雑なアルゴリズムで逃げることができるからです。)

7
これはおそらくだまされていないことに驚いていますが、この挑戦​​は実際に創造的です。
エリックアウトゴルファー

@LeakyNun私はしましたが、過去に、...それについてはあまり心配していないというようなdownvotes(とでも削除票)を得た
エリックOutgolfer

することができますmし、n配列として取られますか?
Okx

回答:



10

オペレーションフラッシュポイントスクリプト言語、98 95バイト

f={t=_this;a=t select 0;b=+a;m=t select 1;n=t select 2;a set[m,b select n];a set[n,b select m]}

配列を直接変更します。

説明:

t=_this;                   // Give a shorter name for the array of arguments.

a=t select 0;              // Let 'a' be a pointer to the array that we modify.
                           // (The language doesn't have a concept of pointers really,
                           // yet its array variables are pointers to the actual array.)

b=+a;                      // Make a copy of the original array and save a pointer to it
                           // in the variable 'b'. This saves a few bytes later.

m=t select 1;              // Read the index arguments from the input array and save them
n=t select 2;              // to their respective variables.

a set[m,b select n];       // Do the swapping by reading the values from the copy and
a set[n,b select m]        // writing them to the original array. The last semicolon can
                           // be omitted because there are no more statements following 
                           // the last statement.

で呼び出す:

array = [1,2,3,4];
str = format["%1", array];
[array, 0, 1] call f;
hint format["%1\n%2", str, array];

出力:

enter image description here


7

JavaScriptのES6、36の 32バイト

ほら、一時変数はありません!

(a,m,n)=>[a[m],a[n]]=[a[n],a[m]]

それを試してみてください

要素のコンマ区切りリストと&のa2つの整数を入力します。mn

f=
(a,m,n)=>[a[m],a[n]]=[a[n],a[m]]
oninput=_=>o.innerText=(f(b=i.value.split`,`,+j.value,+k.value),b);o.innerText=(f(b=(i.value="5,8,9").split`,`,j.value=0,k.value=2),b)
*{font-family:sans-serif}input{margin:0 5px 0 0;width:100px;}#j,#k{width:50px;}
<label for=i>a: </label><input id=i><label for=j>m: </label><input id=j type=number><label for=k>n: </label><input id=k type=number><pre id=o>


2
これらの命令は配列を変更します。つまり、配列を返さないことが許可され、数バイト節約されます。
ニール

@ニール:あなたはただ使うことを言っているの(a,m,n)=>[a[m],a[n]]=[a[n],a[m]]ですか?それは、配列の残りのない2つのスワップされた要素のみを出力します(たとえば、[5,8,9],0,2-> [9,5])。
シャギー

@Neil:そうですa、最後に修正された完全な配列を提供する必要があるのです。または、あなたが言おうとしていることを完全に見逃していますか?
シャギー

@ニール:うーん... OK、私はあなたが今何を得ているかを見ると思う(申し訳ありませんが、今日はあまりにも多くのことをしようとしています)。ヒントをありがとう。それについてコンセンサスがありますか?もしそうなら、自分で検索する前に便利なリンクがありますか?
シャギー



5

ゼリー、7バイト

Ṛ,ḷyJ}ị

オンラインでお試しください!

使い方

Ṛ,ḷyJ}ị  Main link. Left argument: [i, j]. Right argument: A (array)

Ṛ        Reverse; yield [j, i].
  ḷ      Left; yield [i, j].
 ,       Pair; yield [[j, i], [i, j]].
    J}   Indices right; yield all indices of A.
   y     Transliterate; replace j with i and i with j.
      ị  Index into A.

TFWラッパーは...プログラムとほぼ同じ長さ
漏れ修道女

の存在を知らなかったy
リーキー修道女

私は知っていましたがy、ここで使用することを考えていませんでした。それはかなり賢い答えです。

これは私に考えさせられました... Jelly有効なゼリーコードですか?
M.ヘルツカンプ

@ M.Herzkampです。しかし、その非常に有用なことを疑います。
デニス


4

MATL, 7 6 bytes

yyP)w(

Indices are 1-based.

Try it online!

Explanation

Consider inputs [11 13 15 3], [2 3].

yy   % Take two inputs implicitly. Duplicate them
     % STACK: [11 13 15 3], [2 3], [11 13 15 3], [2 3]
P    % Flip
     % STACK: [11 13 15 3], [2 3], [11 13 15 3], [3 2]
)    % Reference indexing (pick indexed entries)
     % STACK: [11 13 15 3], [2 3], [15 13]
w    % Swap
     % STACK: [11 13 15 3], [15 13], [2 3]
(    % Assignment indexing (write values into indexed entries). Implicitly display
     % STACK: [11 15 13 3]

4

C# (.NET Core), 48 43 31 bytes

(a,m,n)=>a[m]+=a[n]-(a[n]=a[m])

Try it online!

Swaps the numbers in the original array, no temporary variables used. Nonetheless I can't take credit for this answer as it has been Neil's idea.


@LeakyNun it does not seem to work, as that leaves a[m] with a value of 0. Try it yourself!
Charlie

(a,m,n)=>a[m]+=a[n]-(a[n]=a[m]) seems to work though.
Neil

(These answers are all also valid in ES6 JavaScript, no?)
Neil


3

Javascript ES6, 36 34 bytes

(a,m,n)=>(x=a[m],a[m]=a[n],a[n]=x)
  • -2 Bytes because the function is altering the array. No need to return the array. Thanks to @Neil

Demo


1
Those instructions modify the array, which means you're allowed to not return the array, which will save you a few bytes.
Neil


2

Java 8, 48 bytes

(a,b,c)->{int t=a[b];a[b]=a[c];a[c]=t;return a;}

Input:

int[] a
int b
int c

How do you do lambdas with three arguments in Java?
Leaky Nun

1
Those instructions modify the array, which means you're allowed to not return the array, which will save you a few bytes.
Neil

1
@LeakyNun I'm not Okx, but here is a Try it now example with Okx's current answer and custom interface.
Kevin Cruijssen

1
And based on Carlos Alejo's amazing C# answer (with @Neil's help), you can make it even shorter by getting rid of the temporary variable: (a,b,c)->a[b]+=a[c]-(a[c]=a[b]) (31 bytes)
Kevin Cruijssen

1
cough cough Collections::swap is 17 bytes... at least assuming this holds for this challenge...
Socratic Phoenix


2

Octave, 28 bytes

@(a,n){a(n)=a(flip(n)),a}{2}

Try it online!

Quite satisfied with this one actually :)

Takes input on the form: f([1,2,3,4],[1,2]), 1-indexed.

Explanation:

@(a,n)                         % Anonymous function that takes two 1-dimensional
                               % arrays as input
      {               , }      % Create a cell with two elements
       a(n)=a(flip(n))         % One element are the two number at indices given by
                               % the second input array. This will be a 1x2 array
      {a(n)=a(flip(n)),a}      % Place those two in a cell together with the entire array a
                               % a is now updated, thanks to Octave's inline assignment
      {a(n)=a(flip(n)),a}{2}   % Return the second element

2

Jellyfish, 7 bytes

p
ZRi
i

Takes a list and a pair of indices. Try it online!

Explanation

Jellyfish happens to have a "modify items at indices" function, Z, which does exactly what we need. The two is grab the inputs from STDIN. Z takes as arguments the second input, the reversal function R, and the list. Then Z performs the modification, and p prints the result.


2

R, 38 bytes

function(x,a,b){x[c(a,b)]=x[c(b,a)];x}

Feels rather long, but I can't get it much shorter. Sadly it requires the explicit returning through x, requiring {} around the function body. pryr::f() doesn't recognise the need for x as function argument so doesn't work :/.


I think function(x,i)replace(x,i,rev(i)) would work, even with pryr syntax.
Giuseppe

@Giuseppe Ah, I was looking for a convenient function to do the swap, but was searching with the wrong terms. Feel free to post that as an own answer.
JAD

@Giuseppe I think you need to do replace(x,i,x[rev(i)]), else you'll place the indices instead of their values.
JAD

2

Shenzhen I/O, 735 Bytes

23¥, 810 Power, 48 Lines of Code

[traces] 
......................
......................
......................
......................
......................
......................
.14.14.14.............
.94.14.14.............
.A........1C..........
.3554..95556..........
.9554.16..............
.A....................
.2....................
......................

[chip] 
[type] UC6
[x] 4
[y] 2
[code] 
  slx x0
  mov x1 acc
  mov x1 dat
  mov acc x3
  mov dat x3
  mov acc x3
  mov dat x3

[chip] 
[type] UC6
[x] 8
[y] 5
[code] 
  slx x2
  mov x2 x1
  mov x0 dat
  mov x2 x1
  mov x0 acc
  mov x2 x1
  mov dat 

[chip] 
[type] UC4X
[x] 2
[y] 6
[code] 
  slx x0
  mov 0 x3
j:  mov x0 acc
  mov acc x2
  teq acc 0
- jmp j
  mov -999 x1

[chip] 
[type] RAM
[x] 5
[y] 6

SIO

DISCLAIMER: Arrays are 0-terminated in this. Arrays are a pain in the ass to work with in Shenzhen I/O otherwise.

I actually made a steam level for this game. You can play it here.

EDIT: Aaand I just realized I said that the array in was ordered. Heck.


Welcome to the site This is really cool! do you think that you might be able to remove some of the whitespace in the file and still have Shenzhen IO accept the file? I don't know how much you have fiddled with it, but you should try and see how flexible the format is.
Wheat Wizard

I haven't played around with it! On the other hand, I am axing the header for the puzzle which contains the puzzle name and solution name, so I dunno if I should bother.
junkmail

1

Swift, 111 65 bytes (0-indexed)

Swift is already notorious for being one of the worst code-golf languages, but here is a function that makes use of ternary expressions:

func t(l:[Int],m:Int,n:Int){var r=l;r[m]=l[n];r[n]=l[m];print(r)}

Check it out! - Usage: t(l:[1,2,3],m:0,n:1).


Using a default param for r would save you bytes and you can also just mutate the passed array (AFAIK swift array are pass by value)
Downgoat

Default parameter in Swift? How can I do that?
Mr. Xcoder

And parameters are constants in Swift @Downgoat
Mr. Xcoder


1

Perl 5, 32 bytes

-3 bytes thanks to @Dom Hastings!

30 bytes of code + -pa flags.

@F[pop@p,@p]=@F[@p=<>];$_="@F"

Try it online!

Quite straight forward, using array slices.


Hey hey, tinkered with this a little and managed to save 3 bytes! @F[pop@p,@p]=@F[@p=<>];$_="@F".
Dom Hastings

@DomHastings Hmm, nice, as always! Thanks :)
Dada

1

Mathematica, 32 bytes

(a=#;a[[{##2}]]=a[[{#3,#2}]];a)&

3
a[[{##2}]]==a[[{#3,#2}]] should be a[[{##2}]]=a[[{#3,#2}]] (using Set, not Equals)
JungHwan Min

1

C, 42 bytes

Modify the array in place with a temp value.

f(r,m,n){int*a=r;r=a[m];a[m]=a[n];a[n]=r;}

C, 60 58 bytes

A little more interesting, not using any temp value...

f(a,m,n)int*a;{a[m]+=a[n];a[n]-=a[m];a[n]*=-1;a[m]-=a[n];}

C, 49 bytes

Using XOR

f(a,m,n)int*a;{a[m]^=a[n];a[n]^=a[m];a[m]^=a[n];}

Heh, I was just about to post f(x,i,j,t)int*x;{t=x[i];x[i]=x[j];x[j]=t;}.
Dennis

@Dennis you saved me two bytes on the other solution, thanks!
cleblanc

Wouldn't the second solution be shorter (and safer) with ^?
Dennis

-1 for the XOR version using a define instead of a function #define X(x,y,z)x[y]^=x[z],x[z]^=x[y],x[y]^=x[z]
Giacomo Garabello

f(r,m,n){int*a=r;r=a[m];a[m]=a[n];a[n]=r;} is broken: SIGSEGV.
Bodo Thiesen

1

Pyth, 17 8 bytes

Saved 9 bytes thanks to Leaky Num.

@LQ.rUQE

Test it online!

This is 0-indexed, and the indices are provided as a tuple: (n, m).

Explanations

@LQ.rUQE

     UQ     # Generate [0, 1, 2, ..., len(input)]
       E    # Get the indices as the tuple (1, 2)
   .r       # Translate each element of UQ to its cyclic successor in E
            # Now the indices are permuted (e.g. [0, 2, 1, ..., len(input)]
@LQ         # For each index, get it's value. Implicit print

8 bytes: @LQ.rUQE
Leaky Nun

@LeakyNun It's so different I think you can post it for yourself!
Jim

I'm the OP; I don't post on my own challenge.
Leaky Nun

1

Mathematica, 20 bytes

#~Permute~Cycles@#2&

Pure function taking two arguments in the following 1-indexed (and possibly abusive) format: the second test case [5,8,9]; 0 2; [9,8,5] would be called as

#~Permute~Cycles@#2& [ {5,8,9} , {{1,3}} ]

(spaces are extraneous and just for visible parsing). Permute is the builtin function that applies a permutation to a list, and Cycles[{{a,b}}] represents the permutation that exchanges the ath and bth elements of a list and ignores the rest.


What do the ~ do?
Cyoce

~ is Mathematica's infix notation for a binary function: x~f~y means the same thing as f[x,y].
Greg Martin

1

x86 Machine Code, 10 bytes

8B 04 8B 87 04 93 89 04 8B C3

This is a function written in 32-bit x86 machine code that swaps the values at the specified indices in a given array. The array is modified in-place, and the function does not return a value.

A custom calling convention is used, requiring the function's parameters to be passed in registers:

  • The address of the array (pointer to its first element) is passed in the EBX register.
  • The zero-based index of element A is passed in the ECX register.
    (Assumed to be a valid index.)
  • The zero-based index of element B is passed in the EDX register.
    (Assumed to be a valid index.)

This keeps the size down and complies with all formal requirements, but does mean that the function cannot be easily called from other languages like C. You'd need to call it from another assembly-language program. (You could rewrite it to use any input registers, though, without affecting the byte count; there's nothing magical about the ones I chose.)

Ungolfed:

8B 04 8B     mov  eax, DWORD PTR [ebx+ecx*4]   ; get value of element A
87 04 93     xchg eax, DWORD PTR [ebx+edx*4]   ; swap element A and element B
89 04 8B     mov  DWORD PTR [ebx+ecx*4], eax   ; store new value for element A
C3           ret                               ; return, with array modified in-place


1

Java 8 + InverseY, 27 bytes

java.util.Collections::swap

Just calls the swap function... this is a method reference of the type Consumer3<List, Integer, Integer>.

Try it online! (header and footer for boilerplate & copy of Consumer3 interface)


You don't need to add " + InverseY". It's valid in vanilla Java 8.
Olivier Grégoire

1

JavaScript (ES2015), 66 57 49 bytes

A different (alas, longer) approach than previous JavaScript answers

(s,h,o,w=s.splice.bind(s))=>w(h,1,...w(o,1,s[h]))

Source

const swap = (arr, a, b, splice) => {
  splice(a, 1, ...splice(arr[b], 1, arr[a]))
}

1
(s,h,o,w=s.splice.bind(s))=>w(h,1,...w(o,1,s[h])) 49 bytes
Patrick Roberts

Forgot about them default args. Thanks!
sshow

0

awk, 31 bytes

{c=$a;$a=$b;$b=c;a=$1;b=$2}NR>1

Try it online!

Takes input in the format

1 2
1 2 3 4

and outputs as

2 1 3 4

(1-indexed).

Explanation

The entire program is a missing pattern with an action followed by a pattern with a missing action.

Since a missing pattern runs on each line, the code inside the braces runs for both input lines. The c=$a;$a=$b;$b=c; part swaps the two values at indices a and b (through the temporary variable c). This only has an effect on the second line, since on the first line a and b are not yet defined. The a=$1;b=$2 part defines a to be the first field and b to be the second field, which sets the appropriate values for the first part to run on the second line.

Since a missing action is equivalent to {print}, the pattern prints every line it matches. This pattern in particular is NR>1: that is, print whenever the line number is greater than 1, which happens to be line 2. This runs after the swapping of values has taken place, thus completing the task.


0

q/kdb+, 17 bytes

Solution:

{@[x;(|)y;:;x y]}

Example:

q){@[x;(|)y;:;x y]}[1 2 3 4;0 1]
2 1 3 4

Explanation:

A q version of the k answer by Simon. Apply the assign : function to x at indices reverse-y with value of x indexed at y. Broken down you can see more clearly:

q)x:1 2 3 4
q)y:0 1
q)x y
1 2
q)(|)y
1 0
q)x(|)y
2 1
q)@[x;(|)y;:;x y]
2 1 3 4
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